double log1p (double x); float log1pf (float x);long double log1pl (long double x);
double log1p (double x); float log1p (float x);long double log1p (long double x); double log1p (T x); // additional overloads for integral types
log(1+x)
更精確。-1
,則會發生定義域錯誤。(1+x)
的自然對數。-1
,會導致定義域錯誤。-1
,可能會導致極點錯誤(取決於庫的實現)。
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log1p (1.000000) = 0.693147 |